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% Defined simulation of tanker with PD controller
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%
% By: Kevin Passino
% Version: 4/13/01
%
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function Jcl=pdtanker(KPKD,w1,w2);
Kp=KPKD(1,1);
Kd=KPKD(2,1);
% Initialize ship parameters
% (can test two conditions, "ballast" or "full"):
ell=350; % Length of the ship (in meters)
u=5; % Nominal speed (in meters/sec)
abar=1; % Parameters for nonlinearity
bbar=1;
% Define the reference model (we use a first order transfer function
% k_r/(s+a_r)):
a_r=1/150;
k_r=1/150;
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% Simulate the controller regulating the ship heading
% Next, we initialize the simulation:
t=0; % Reset time to zero
index=1; % This is time's index (not time, its index).
tstop=1200; % Stopping time for the simulation (in seconds) - normally 20000
step=1; % Integration step size
T=10; % The controller is implemented in discrete time and
% this is the sampling time for the controller.
% Note that the integration step size and the sampling
% time are not the same. In this way we seek to simulate
% the continuous time system via the Runge-Kutta method and
% the discrete time controller as if it were
% implemented by a digital computer. Hence, we sample
% the plant output every T seconds and at that time
% output a new value of the controller output.
counter=10; % This counter will be used to count the number of integration
% steps that have been taken in the current sampling interval.
% Set it to 10 to begin so that it will compute a controller
% output at the first step.
% For our example, when 10 integration steps have been
% taken we will then we will sample the ship heading
% and the reference heading and compute a new output
% for the controller.
eold=0; % Initialize the past value of the error (for use
% in computing the change of the error, c). Notice
% that this is somewhat of an arbitrary choice since
% there is no last time step. The same problem is
% encountered in implementation.
cold=0; % Need this to initialize phiold below
psi_r_old=0; % Initialize the reference trajectory
ymold=0; % Initial condition for the first order reference model
x=[0;0;0]; % First, set the state to be a vector
x(1)=0; % Set the initial heading to be zero
x(2)=0; % Set the initial heading rate to be zero.
% We would also like to set x(3) initially but this
% must be done after we have computed the output
% of the controller. In this case, by
% choosing the reference trajectory to be
% zero at the beginning and the other initial conditions
% as they are, and the controller as designed,
% we will know that the output of the controller
% will start out at zero so we could have set
% x(3)=0 here. To keep things more general, however,
% we set the intial condition immediately after
% we compute the first controller output in the
% loop below.
% Next, we start the simulation of the system. This is the main
% loop for the simulation of the control system.
psi_r=0*ones(1,tstop+1);
psi=0*ones(1,tstop+1);
e=0*ones(1,tstop+1);
c=0*ones(1,tstop+1);
s=0*ones(1,tstop+1);
w=0*ones(1,tstop+1);
delta=0*ones(1,tstop+1);
ym=0*ones(1,tstop+1);
while t <= tstop
% First, we define the reference input psi_r (desired heading).
if t>=0, psi_r(index)=0; end % Request heading of 0 deg
if t>=100, psi_r(index)=45*(pi/180); end % Request heading of 45 deg
if t>=1500, psi_r(index)=0; end % Request heading of 0 deg
if t>=3000, psi_r(index)=45*(pi/180); end % Request heading of -45 deg
if t>=4500, psi_r(index)=0; end % Request heading of 0 deg
if t>=6000, psi_r(index)=45*(pi/180); end % Request heading of 45 deg
if t>=7500, psi_r(index)=0; end % Request heading of 0 deg
if t>=9000, psi_r(index)=45*(pi/180); end % Request heading of 45 deg
if t>=10500, psi_r(index)=0; end % Request heading of 0 deg
if t>=12000, psi_r(index)=45*(pi/180); end % Request heading of -45 deg
if t>=13500, psi_r(index)=0; end % Request heading of 0 deg
if t>=15000, psi_r(index)=45*(pi/180); end % Request heading of 45 deg
if t>=16500, psi_r(index)=0; end % Request heading of 0 deg
if t>=18000, psi_r(index)=45*(pi/180); end % Request heading of 45 deg
if t>=19500, psi_r(index)=0; end % Request heading of 0 deg
% Next, suppose that there is sensor noise for the heading sensor with that is
% additive, with a uniform distribution on [- 0.01,+0.01] deg.
s(index)=0.01*(pi/180)*(2*rand-1); %else
%s(index)=0; % This allows us to remove the noise.
%end
psi(index)=x(1)+s(index); % Heading of the ship (possibly with sensor noise).
if counter == 10, % When the counter reaches 10 then execute the
% controller
counter=0; % First, reset the counter
% Reference model calculations:
% The reference model is part of the controller and to simulate it
% we take the discrete equivalent of the
% reference model to compute psi_m from psi_r (if you use
% a continuous-time reference model you will have to augment
% the state of the closed-loop system with the state(s) of the
% reference model and hence update the state in the Runge-Kutta
% equations).
%
% For the reference model we use a first order transfer function
% k_r/(s+a_r) but we use the bilinear transformation where we
% replace s by (2/step)(z-1)/(z+1), then find the z-domain
% representation of the reference model, then convert this
% to a difference equation:
ym(index)=(1/(2+a_r*T))*((2-a_r*T)*ymold+...
k_r*T*(psi_r(index)+psi_r_old));
ymold=ym(index);
psi_r_old=psi_r(index);
% This saves the past value of the ym and psi_r so that we can use it
% the next time around the loop
% Controller calculations:
e(index)=psi_r(index)-psi(index); % Computes error (first layer of perceptron)
c(index)=(e(index)-eold)/T; % Sets the value of c
eold=e(index); % Save the past value of e for use in the above
% computation the next time around the loop
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% A proportional-derivative controller:
delta(index)=Kp*e(index)+Kd*c(index);
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else % This goes with the "if" statement to check if the counter=10
% so the next lines up to the next "end" statement are executed
% whenever counter is not equal to 10
% Now, even though we do not compute the controller at each
% time instant, we do want to save the data at its inputs and output at
% each time instant for the sake of plotting it. Hence, we need to
% compute these here (note that we simply hold the values constant):
e(index)=e(index-1);
c(index)=c(index-1);
delta(index)=delta(index-1);
ym(index)=ym(index-1);
end % This is the end statement for the "if counter=10" statement
% Next, the Runge-Kutta equations are used to find the next state.
% Clearly, it would be better to use a Matlab "function" for
% F (but here we do not, so we can have only one program).
time(index)=t;
% First, we define a wind disturbance against the body of the ship
% that has the effect of pressing water against the rudder
%if flag==0, w(index)=0.5*(pi/180)*sin(2*pi*0.001*t); % This is an additive sine disturbance to
% the rudder input. It is of amplitude of
% 0.5 deg. and its period is 1000sec.
%delta(index)=delta(index)+w(index);
%end
% Next, implement the nonlinearity where the rudder angle is saturated
% at +-80 degrees
if delta(index) >= 80*(pi/180), delta(index)=80*(pi/180); end
if delta(index) <= -80*(pi/180), delta(index)=-80*(pi/180); end
% The next line is used in place of the line following it to
% change the speed of the ship
%if flag==0,
%%if t>=1000000,
%%if t>=9000, % This switches the ship speed (unrealistically fast)
%u=3; % A lower speed
%else
u=5;
%end
% Next, we change the parameters of the ship to tanker to reflect
% changing loading conditions (note that we simulate as if
% the ship is loaded while moving, but we only change the parameters
% while the heading is zero so that it is then similar to re-running
% the simulation, i.e., starting the tanker operation at different
% times after loading/unloading has occurred).
% The next line is used in place of the line following it to keep
% "ballast" conditions throughout the simulation
if t>=1000000,
%if t>=0, % This switches the parameters, possibly in the middle of the simulation
K_0=0.83; % These are the parameters under "full" conditions
tau_10=-2.88;
tau_20=0.38;
tau_30=1.07;
else
K_0=5.88; % These are the parameters under "ballast" conditions
tau_10=-16.91;
tau_20=0.45;
tau_30=1.43;
end
% The following parameters are used in the definition of the tanker model:
K=K_0*(u/ell);
tau_1=tau_10*(ell/u);
tau_2=tau_20*(ell/u);
tau_3=tau_30*(ell/u);
% Next, comes the plant:
% Now, for the first step, we set the initial condition for the
% third state x(3).
if t==0, x(3)=-(K*tau_3/(tau_1*tau_2))*delta(index); end
% Next, we use the formulas to implement the Runge-Kutta method
% (note that here only an approximation to the method is implemented where
% we do not compute the function at multiple points in the integration step size).
F=[ x(2) ;
x(3)+ (K*tau_3/(tau_1*tau_2))*delta(index) ;
-((1/tau_1)+(1/tau_2))*(x(3)+ (K*tau_3/(tau_1*tau_2))*delta(index))-...
(1/(tau_1*tau_2))*(abar*x(2)^3 + bbar*x(2)) + (K/(tau_1*tau_2))*delta(index) ];
k1=step*F;
xnew=x+k1/2;
F=[ xnew(2) ;
xnew(3)+ (K*tau_3/(tau_1*tau_2))*delta(index) ;
-((1/tau_1)+(1/tau_2))*(xnew(3)+ (K*tau_3/(tau_1*tau_2))*delta(index))-...
(1/(tau_1*tau_2))*(abar*xnew(2)^3 + bbar*xnew(2)) + (K/(tau_1*tau_2))*delta(index) ];
k2=step*F;
xnew=x+k2/2;
F=[ xnew(2) ;
xnew(3)+ (K*tau_3/(tau_1*tau_2))*delta(index) ;
-((1/tau_1)+(1/tau_2))*(xnew(3)+ (K*tau_3/(tau_1*tau_2))*delta(index))-...
(1/(tau_1*tau_2))*(abar*xnew(2)^3 + bbar*xnew(2)) + (K/(tau_1*tau_2))*delta(index) ];
k3=step*F;
xnew=x+k3;
F=[ xnew(2) ;
xnew(3)+ (K*tau_3/(tau_1*tau_2))*delta(index) ;
-((1/tau_1)+(1/tau_2))*(xnew(3)+ (K*tau_3/(tau_1*tau_2))*delta(index))-...
(1/(tau_1*tau_2))*(abar*xnew(2)^3 + bbar*xnew(2)) + (K/(tau_1*tau_2))*delta(index) ];
k4=step*F;
x=x+(1/6)*(k1+2*k2+2*k3+k4); % Calculated next state
t=t+step; % Increments time
index=index+1; % Increments the indexing term so that
% index=1 corresponds to time t=0.
counter=counter+1; % Indicates that we computed one more integration step
end % This end statement goes with the first "while" statement
% in the program so when this is complete the simulation is done.
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% Compute how well the controller did in terms of deviation
% from the reference model and the control energy
Jcl=w1*(psi-ym)*(psi-ym)'+w2*delta*delta';
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% End of program %
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